Question
Answer
$$\dfrac{m^2-4}{m^2+6m+8}=\dfrac{m-2}{m+4}$$
Explanation
| $$ \begin{aligned}\frac{m^2-4}{m^2+6m+8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{m-2}{m+4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{m^2-4}{m^2+6m+8} $ to $ \dfrac{m-2}{m+4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{m+2}$. $$ \begin{aligned} \frac{m^2-4}{m^2+6m+8} & =\frac{ \left( m-2 \right) \cdot \color{blue}{ \left( m+2 \right) }}{ \left( m+4 \right) \cdot \color{blue}{ \left( m+2 \right) }} = \\[1ex] &= \frac{m-2}{m+4} \end{aligned} $$ |
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Simplify Rational Expressions