Question
Answer
$$\dfrac{g^2+7g+10}{g^2+5g+6}=\dfrac{g+5}{g+3}$$
Explanation
| $$ \begin{aligned}\frac{g^2+7g+10}{g^2+5g+6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{g+5}{g+3}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{g^2+7g+10}{g^2+5g+6} $ to $ \dfrac{g+5}{g+3} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{g+2}$. $$ \begin{aligned} \frac{g^2+7g+10}{g^2+5g+6} & =\frac{ \left( g+5 \right) \cdot \color{blue}{ \left( g+2 \right) }}{ \left( g+3 \right) \cdot \color{blue}{ \left( g+2 \right) }} = \\[1ex] &= \frac{g+5}{g+3} \end{aligned} $$ |
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Simplify Rational Expressions