Question
Answer
$$\dfrac{d-3}{d^3-17d^2+42d}=\dfrac{1}{d^2-14d}$$
Explanation
| $$ \begin{aligned}\frac{d-3}{d^3-17d^2+42d}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{d^2-14d}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{d-3}{d^3-17d^2+42d} $ to $ \dfrac{1}{d^2-14d} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{d-3}$. $$ \begin{aligned} \frac{d-3}{d^3-17d^2+42d} & =\frac{ 1 \cdot \color{blue}{ \left( d-3 \right) }}{ \left( d^2-14d \right) \cdot \color{blue}{ \left( d-3 \right) }} = \\[1ex] &= \frac{1}{d^2-14d} \end{aligned} $$ |
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Simplify Rational Expressions