Question
Answer
$$\dfrac{d^2-8d+15}{d-5}=d-3$$
Explanation
| $$ \begin{aligned}\frac{d^2-8d+15}{d-5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}d-3\end{aligned} $$ | |
| ① | Simplify $ \dfrac{d^2-8d+15}{d-5} $ to $ d-3$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{d-5}$. $$ \begin{aligned} \frac{d^2-8d+15}{d-5} & =\frac{ \left( d-3 \right) \cdot \color{blue}{ \left( d-5 \right) }}{ 1 \cdot \color{blue}{ \left( d-5 \right) }} = \\[1ex] &= \frac{d-3}{1} =d-3 \end{aligned} $$ |
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Simplify Rational Expressions