Question
Answer
$$(b^3+b^2-51b-45)\cdot7=7b^3+7b^2-357b-315$$
Explanation
| $$ \begin{aligned}(b^3+b^2-51b-45)\cdot7& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7b^3+7b^2-357b-315\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{b^3+b^2-51b-45}\right) \cdot 7 = 7b^3+7b^2-357b-315 $$ |
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Simplify Rational Expressions