Question
Answer
$$\dfrac{b^2+9b-10}{b-1}=b+10$$
Explanation
| $$ \begin{aligned}\frac{b^2+9b-10}{b-1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}b+10\end{aligned} $$ | |
| ① | Simplify $ \dfrac{b^2+9b-10}{b-1} $ to $ b+10$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{b-1}$. $$ \begin{aligned} \frac{b^2+9b-10}{b-1} & =\frac{ \left( b+10 \right) \cdot \color{blue}{ \left( b-1 \right) }}{ 1 \cdot \color{blue}{ \left( b-1 \right) }} = \\[1ex] &= \frac{b+10}{1} =b+10 \end{aligned} $$ |
This page was created using
Simplify Rational Expressions