Question
Answer
$$(a-3)(a-3)=a^2-6a+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(a-3)(a-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}a^2-3a-3a+9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}a^2-6a+9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{a-3}\right) $ by each term in $ \left( a-3\right) $. $$ \left( \color{blue}{a-3}\right) \cdot \left( a-3\right) = a^2-3a-3a+9 $$ |
| ② | Combine like terms: $$ a^2 \color{blue}{-3a} \color{blue}{-3a} +9 = a^2 \color{blue}{-6a} +9 $$ |
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Simplify Rational Expressions