Question
Answer
$$\dfrac{9x+9}{x-7}+\dfrac{3x+4}{x-7}=\dfrac{12x+13}{x-7}$$
Explanation
| $$ \begin{aligned}\frac{9x+9}{x-7}+\frac{3x+4}{x-7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{12x+13}{x-7}\end{aligned} $$ | |
| ① | Add $ \dfrac{9x+9}{x-7} $ and $ \dfrac{3x+4}{x-7} $ to get $ \dfrac{12x+13}{x-7} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{9x+9}{x-7} + \frac{3x+4}{x-7} & = \frac{9x+9}{\color{blue}{x-7}} + \frac{3x+4}{\color{blue}{x-7}} = \\[1ex] &=\frac{ 9x+9 + \left( 3x+4 \right) }{ \color{blue}{ x-7 }}= \frac{12x+13}{x-7} \end{aligned} $$ |
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Simplify Rational Expressions