Question
Answer
$$\dfrac{9x^2-81x+180}{6x^2-36x+30}=\dfrac{3x-12}{2x-2}$$
Explanation
| $$ \begin{aligned}\frac{9x^2-81x+180}{6x^2-36x+30}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3x-12}{2x-2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{9x^2-81x+180}{6x^2-36x+30} $ to $ \dfrac{3x-12}{2x-2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3x-15}$. $$ \begin{aligned} \frac{9x^2-81x+180}{6x^2-36x+30} & =\frac{ \left( 3x-12 \right) \cdot \color{blue}{ \left( 3x-15 \right) }}{ \left( 2x-2 \right) \cdot \color{blue}{ \left( 3x-15 \right) }} = \\[1ex] &= \frac{3x-12}{2x-2} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions