Question
Answer
$$\dfrac{9x^2-26x+30}{(2x-3)(x+6)}=\dfrac{9x^2-26x+30}{2x^2+9x-18}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{9x^2-26x+30}{(2x-3)(x+6)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{9x^2-26x+30}{2x^2+12x-3x-18} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{9x^2-26x+30}{2x^2+9x-18}\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-3}\right) $ by each term in $ \left( x+6\right) $. $$ \left( \color{blue}{2x-3}\right) \cdot \left( x+6\right) = 2x^2+12x-3x-18 $$ |
| ② | Simplify denominator $$ 2x^2+ \color{blue}{12x} \color{blue}{-3x} -18 = 2x^2+ \color{blue}{9x} -18 $$ |
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