Question
Answer
$$\dfrac{9x^2+55x+6}{x+6}=9x+1$$
Explanation
| $$ \begin{aligned}\frac{9x^2+55x+6}{x+6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x+1\end{aligned} $$ | |
| ① | Simplify $ \dfrac{9x^2+55x+6}{x+6} $ to $ 9x+1$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+6}$. $$ \begin{aligned} \frac{9x^2+55x+6}{x+6} & =\frac{ \left( 9x+1 \right) \cdot \color{blue}{ \left( x+6 \right) }}{ 1 \cdot \color{blue}{ \left( x+6 \right) }} = \\[1ex] &= \frac{9x+1}{1} =9x+1 \end{aligned} $$ |
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Simplify Rational Expressions