Question
Answer
$$\dfrac{9r^3+42r^2+49r}{3r+7}=3r^2+7r$$
Explanation
| $$ \begin{aligned}\frac{9r^3+42r^2+49r}{3r+7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3r^2+7r\end{aligned} $$ | |
| ① | Simplify $ \dfrac{9r^3+42r^2+49r}{3r+7} $ to $ 3r^2+7r$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3r+7}$. $$ \begin{aligned} \frac{9r^3+42r^2+49r}{3r+7} & =\frac{ \left( 3r^2+7r \right) \cdot \color{blue}{ \left( 3r+7 \right) }}{ 1 \cdot \color{blue}{ \left( 3r+7 \right) }} = \\[1ex] &= \frac{3r^2+7r}{1} =3r^2+7r \end{aligned} $$ |
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Simplify Rational Expressions