Question
Answer
$$\dfrac{9r^2+45r}{r+5}=9r$$
Explanation
| $$ \begin{aligned}\frac{9r^2+45r}{r+5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9r\end{aligned} $$ | |
| ① | Simplify $ \dfrac{9r^2+45r}{r+5} $ to $ 9r$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{r+5}$. $$ \begin{aligned} \frac{9r^2+45r}{r+5} & =\frac{ 9r \cdot \color{blue}{ \left( r+5 \right) }}{ 1 \cdot \color{blue}{ \left( r+5 \right) }} = \\[1ex] &= \frac{9r}{1} =9r \end{aligned} $$ |
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Simplify Rational Expressions