Question
Answer
$$\dfrac{9b^2+24b+16}{3b+4}=3b+4$$
Explanation
| $$ \begin{aligned}\frac{9b^2+24b+16}{3b+4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3b+4\end{aligned} $$ | |
| ① | Simplify $ \dfrac{9b^2+24b+16}{3b+4} $ to $ 3b+4$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3b+4}$. $$ \begin{aligned} \frac{9b^2+24b+16}{3b+4} & =\frac{ \left( 3b+4 \right) \cdot \color{blue}{ \left( 3b+4 \right) }}{ 1 \cdot \color{blue}{ \left( 3b+4 \right) }} = \\[1ex] &= \frac{3b+4}{1} =3b+4 \end{aligned} $$ |
This page was created using
Simplify Rational Expressions