Question
Answer
$$\dfrac{8x+8}{x-9}+\dfrac{7x+9}{x-9}=\dfrac{15x+17}{x-9}$$
Explanation
| $$ \begin{aligned}\frac{8x+8}{x-9}+\frac{7x+9}{x-9}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{15x+17}{x-9}\end{aligned} $$ | |
| ① | Add $ \dfrac{8x+8}{x-9} $ and $ \dfrac{7x+9}{x-9} $ to get $ \dfrac{15x+17}{x-9} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{8x+8}{x-9} + \frac{7x+9}{x-9} & = \frac{8x+8}{\color{blue}{x-9}} + \frac{7x+9}{\color{blue}{x-9}} = \\[1ex] &=\frac{ 8x+8 + \left( 7x+9 \right) }{ \color{blue}{ x-9 }}= \frac{15x+17}{x-9} \end{aligned} $$ |
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Simplify Rational Expressions