Question
Answer
$$\dfrac{8x^4y^2}{3z^3}\dfrac{9xy^2z^6}{4y^4}=\dfrac{72x^5y^4z^6}{12y^4z^3}$$
Explanation
| $$ \begin{aligned}\frac{8x^4y^2}{3z^3}\frac{9xy^2z^6}{4y^4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{72x^5y^4z^6}{12y^4z^3}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{8x^4y^2}{3z^3} $ by $ \dfrac{9xy^2z^6}{4y^4} $ to get $ \dfrac{ 72x^5y^4z^6 }{ 12y^4z^3 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{8x^4y^2}{3z^3} \cdot \frac{9xy^2z^6}{4y^4} & \xlongequal{\text{Step 1}} \frac{ 8x^4y^2 \cdot 9xy^2z^6 }{ 3z^3 \cdot 4y^4 } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 72x^5y^4z^6 }{ 12y^4z^3 } \end{aligned} $$ |
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