Question
Answer
$$\dfrac{8x^2-44x+60}{6x^2+18x-108}=\dfrac{4x-10}{3x+18}$$
Explanation
| $$ \begin{aligned}\frac{8x^2-44x+60}{6x^2+18x-108}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4x-10}{3x+18}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{8x^2-44x+60}{6x^2+18x-108} $ to $ \dfrac{4x-10}{3x+18} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2x-6}$. $$ \begin{aligned} \frac{8x^2-44x+60}{6x^2+18x-108} & =\frac{ \left( 4x-10 \right) \cdot \color{blue}{ \left( 2x-6 \right) }}{ \left( 3x+18 \right) \cdot \color{blue}{ \left( 2x-6 \right) }} = \\[1ex] &= \frac{4x-10}{3x+18} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions