Question
Answer
$$\dfrac{8x^2-14x+6}{4x-3}=2x-2$$
Explanation
| $$ \begin{aligned}\frac{8x^2-14x+6}{4x-3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x-2\end{aligned} $$ | |
| ① | Simplify $ \dfrac{8x^2-14x+6}{4x-3} $ to $ 2x-2$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{4x-3}$. $$ \begin{aligned} \frac{8x^2-14x+6}{4x-3} & =\frac{ \left( 2x-2 \right) \cdot \color{blue}{ \left( 4x-3 \right) }}{ 1 \cdot \color{blue}{ \left( 4x-3 \right) }} = \\[1ex] &= \frac{2x-2}{1} =2x-2 \end{aligned} $$ |
This page was created using
Simplify Rational Expressions