Question
Answer
$$\dfrac{8m^2-32m}{m^2-12m+32}=\dfrac{8m}{m-8}$$
Explanation
| $$ \begin{aligned}\frac{8m^2-32m}{m^2-12m+32}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{8m}{m-8}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{8m^2-32m}{m^2-12m+32} $ to $ \dfrac{8m}{m-8} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{m-4}$. $$ \begin{aligned} \frac{8m^2-32m}{m^2-12m+32} & =\frac{ 8m \cdot \color{blue}{ \left( m-4 \right) }}{ \left( m-8 \right) \cdot \color{blue}{ \left( m-4 \right) }} = \\[1ex] &= \frac{8m}{m-8} \end{aligned} $$ |
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Simplify Rational Expressions