Question
Answer
$$\dfrac{7x-1}{3}+\dfrac{x+6}{3}=\dfrac{8x+5}{3}$$
Explanation
| $$ \begin{aligned}\frac{7x-1}{3}+\frac{x+6}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{8x+5}{3}\end{aligned} $$ | |
| ① | Add $ \dfrac{7x-1}{3} $ and $ \dfrac{x+6}{3} $ to get $ \dfrac{8x+5}{3} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{7x-1}{3} + \frac{x+6}{3} & = \frac{7x-1}{\color{blue}{3}} + \frac{x+6}{\color{blue}{3}} =\frac{ 7x-1 + \left( x+6 \right) }{ \color{blue}{ 3 }} = \\[1ex] &= \frac{8x+5}{3} \end{aligned} $$ |
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Simplify Rational Expressions