Question
Answer
$$\dfrac{7x^3+14x+7}{(x^2-1)(x+1)}=\dfrac{7x^3+14x+7}{x^3+x^2-x-1}$$
Explanation
| $$ \begin{aligned}\frac{7x^3+14x+7}{(x^2-1)(x+1)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7x^3+14x+7}{x^3+x^2-x-1}\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^2-1}\right) $ by each term in $ \left( x+1\right) $. $$ \left( \color{blue}{x^2-1}\right) \cdot \left( x+1\right) = x^3+x^2-x-1 $$ |
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Simplify Rational Expressions