Question
Answer
$$\dfrac{7x^3-56x^2}{x^2+x-72}=\dfrac{7x^2}{x+9}$$
Explanation
| $$ \begin{aligned}\frac{7x^3-56x^2}{x^2+x-72}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7x^2}{x+9}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{7x^3-56x^2}{x^2+x-72} $ to $ \dfrac{7x^2}{x+9} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x-8}$. $$ \begin{aligned} \frac{7x^3-56x^2}{x^2+x-72} & =\frac{ 7x^2 \cdot \color{blue}{ \left( x-8 \right) }}{ \left( x+9 \right) \cdot \color{blue}{ \left( x-8 \right) }} = \\[1ex] &= \frac{7x^2}{x+9} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions