Question
Answer
$$\dfrac{7v-35}{25-v^2}=\dfrac{7}{-v-5}$$
Explanation
| $$ \begin{aligned}\frac{7v-35}{25-v^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7}{-v-5}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{7v-35}{25-v^2} $ to $ \dfrac{7}{-v-5} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{v-5}$. $$ \begin{aligned} \frac{7v-35}{25-v^2} & =\frac{ 7 \cdot \color{blue}{ \left( v-5 \right) }}{ \left( -v-5 \right) \cdot \color{blue}{ \left( v-5 \right) }} = \\[1ex] &= \frac{7}{-v-5} \end{aligned} $$ |
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Simplify Rational Expressions