Question
Answer
$$\dfrac{7n-42}{36-n^2}=\dfrac{7}{-n-6}$$
Explanation
| $$ \begin{aligned}\frac{7n-42}{36-n^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7}{-n-6}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{7n-42}{36-n^2} $ to $ \dfrac{7}{-n-6} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{n-6}$. $$ \begin{aligned} \frac{7n-42}{36-n^2} & =\frac{ 7 \cdot \color{blue}{ \left( n-6 \right) }}{ \left( -n-6 \right) \cdot \color{blue}{ \left( n-6 \right) }} = \\[1ex] &= \frac{7}{-n-6} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions