Question
Answer
$$\dfrac{7m-35}{5-m}=-7$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{7m-35}{5-m}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7}{-1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-\frac{7}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-7\end{aligned} $$ | |
| ① | Simplify $ \dfrac{7m-35}{5-m} $ to $ \dfrac{7}{-1} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{m-5}$. $$ \begin{aligned} \frac{7m-35}{5-m} & =\frac{ 7 \cdot \color{blue}{ \left( m-5 \right) }}{ \left( -1 \right) \cdot \color{blue}{ \left( m-5 \right) }} = \\[1ex] &= \frac{7}{-1} \end{aligned} $$ |
| ② | Place minus sign in front of the fraction. |
| ③ | Remove 1 from denominator. |
This page was created using
Simplify Rational Expressions