| $$ \begin{aligned}\frac{7b^2-42b}{b-6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7b\end{aligned} $$ | |
| ① | Simplify $ \dfrac{7b^2-42b}{b-6} $ to $ 7b$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{b-6}$. $$ \begin{aligned} \frac{7b^2-42b}{b-6} & =\frac{ 7b \cdot \color{blue}{ \left( b-6 \right) }}{ 1 \cdot \color{blue}{ \left( b-6 \right) }} = \\[1ex] &= \frac{7b}{1} =7b \end{aligned} $$ |