Question
Answer
$$\dfrac{6x-9}{2x-3}=3$$
Explanation
| $$ \begin{aligned}\frac{6x-9}{2x-3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3\end{aligned} $$ | |
| ① | Simplify $ \dfrac{6x-9}{2x-3} $ to $ 3$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2x-3}$. $$ \begin{aligned} \frac{6x-9}{2x-3} & =\frac{ 3 \cdot \color{blue}{ \left( 2x-3 \right) }}{ 1 \cdot \color{blue}{ \left( 2x-3 \right) }} = \\[1ex] &= \frac{3}{1} =3 \end{aligned} $$ |
This page was created using
Simplify Rational Expressions