Question
Answer
$$\dfrac{6x^3y}{xy^2}\dfrac{3x^2y}{8x^3}=\dfrac{18x^5y^2}{8x^4y^2}$$
Explanation
| $$ \begin{aligned}\frac{6x^3y}{xy^2}\frac{3x^2y}{8x^3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{18x^5y^2}{8x^4y^2}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{6x^3y}{xy^2} $ by $ \dfrac{3x^2y}{8x^3} $ to get $ \dfrac{ 18x^5y^2 }{ 8x^4y^2 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{6x^3y}{xy^2} \cdot \frac{3x^2y}{8x^3} & \xlongequal{\text{Step 1}} \frac{ 6x^3y \cdot 3x^2y }{ xy^2 \cdot 8x^3 } \xlongequal{\text{Step 2}} \frac{ 18x^5y^2 }{ 8x^4y^2 } \end{aligned} $$ |
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