Question
Answer
$$\dfrac{6x^2+66x+60}{2x^3+2x^2-180x}=\dfrac{3x+3}{x^2-9x}$$
Explanation
| $$ \begin{aligned}\frac{6x^2+66x+60}{2x^3+2x^2-180x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3x+3}{x^2-9x}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{6x^2+66x+60}{2x^3+2x^2-180x} $ to $ \dfrac{3x+3}{x^2-9x} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2x+20}$. $$ \begin{aligned} \frac{6x^2+66x+60}{2x^3+2x^2-180x} & =\frac{ \left( 3x+3 \right) \cdot \color{blue}{ \left( 2x+20 \right) }}{ \left( x^2-9x \right) \cdot \color{blue}{ \left( 2x+20 \right) }} = \\[1ex] &= \frac{3x+3}{x^2-9x} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions