Question
Answer
$$\dfrac{6x}{7}-\dfrac{2x}{7}=\dfrac{4x}{7}$$
Explanation
| $$ \begin{aligned}\frac{6x}{7}-\frac{2x}{7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4x}{7}\end{aligned} $$ | |
| ① | Subtract $ \dfrac{2x}{7} $ from $ \dfrac{6x}{7} $ to get $ \dfrac{4x}{7} $. To subtract expressions with the same denominators, we subtract the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{6x}{7} - \frac{2x}{7} & = \frac{6x}{\color{blue}{7}} - \frac{2x}{\color{blue}{7}} =\frac{ 6x - 2x }{ \color{blue}{ 7 }} = \\[1ex] &= \frac{4x}{7} \end{aligned} $$ |
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Simplify Rational Expressions