Question
Answer
$$\dfrac{6n^2+45n+39}{30n+30}=\dfrac{2n+13}{10}$$
Explanation
| $$ \begin{aligned}\frac{6n^2+45n+39}{30n+30}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2n+13}{10}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{6n^2+45n+39}{30n+30} $ to $ \dfrac{2n+13}{10} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3n+3}$. $$ \begin{aligned} \frac{6n^2+45n+39}{30n+30} & =\frac{ \left( 2n+13 \right) \cdot \color{blue}{ \left( 3n+3 \right) }}{ 10 \cdot \color{blue}{ \left( 3n+3 \right) }} = \\[1ex] &= \frac{2n+13}{10} \end{aligned} $$ |
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Simplify Rational Expressions