Question
Answer
$$\dfrac{6a^2+12a}{9a^3+18a^2}=\dfrac{2}{3a}$$
Explanation
| $$ \begin{aligned}\frac{6a^2+12a}{9a^3+18a^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2}{3a}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{6a^2+12a}{9a^3+18a^2} $ to $ \dfrac{2}{3a} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3a^2+6a}$. $$ \begin{aligned} \frac{6a^2+12a}{9a^3+18a^2} & =\frac{ 2 \cdot \color{blue}{ \left( 3a^2+6a \right) }}{ 3a \cdot \color{blue}{ \left( 3a^2+6a \right) }} = \\[1ex] &= \frac{2}{3a} \end{aligned} $$ |
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Simplify Rational Expressions