Question
Answer
$$\dfrac{6a^2-24a+24}{6a^2-24}=\dfrac{a-2}{a+2}$$
Explanation
| $$ \begin{aligned}\frac{6a^2-24a+24}{6a^2-24}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{a-2}{a+2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{6a^2-24a+24}{6a^2-24} $ to $ \dfrac{a-2}{a+2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{6a-12}$. $$ \begin{aligned} \frac{6a^2-24a+24}{6a^2-24} & =\frac{ \left( a-2 \right) \cdot \color{blue}{ \left( 6a-12 \right) }}{ \left( a+2 \right) \cdot \color{blue}{ \left( 6a-12 \right) }} = \\[1ex] &= \frac{a-2}{a+2} \end{aligned} $$ |
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Simplify Rational Expressions