Question
Answer
$$\dfrac{6a^2}{5b^2}\dfrac{25a^2}{36b}=\dfrac{150a^4}{180b^3}$$
Explanation
| $$ \begin{aligned}\frac{6a^2}{5b^2}\frac{25a^2}{36b}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{150a^4}{180b^3}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{6a^2}{5b^2} $ by $ \dfrac{25a^2}{36b} $ to get $ \dfrac{ 150a^4 }{ 180b^3 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{6a^2}{5b^2} \cdot \frac{25a^2}{36b} & \xlongequal{\text{Step 1}} \frac{ 6a^2 \cdot 25a^2 }{ 5b^2 \cdot 36b } \xlongequal{\text{Step 2}} \frac{ 150a^4 }{ 180b^3 } \end{aligned} $$ |
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