Question
Answer
$$\dfrac{6^2+66x+60}{2x^3+2x^2-180x}=\dfrac{33x+48}{x^3+x^2-90x}$$
Explanation
| $$ \begin{aligned}\frac{6^2+66x+60}{2x^3+2x^2-180x}& \xlongequal{ }\frac{36+66x+60}{2x^3+2x^2-180x} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{66x+96}{2x^3+2x^2-180x} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{33x+48}{x^3+x^2-90x}\end{aligned} $$ | |
| ① | Simplify numerator $$ \color{blue}{36} +66x+ \color{blue}{60} = 66x+ \color{blue}{96} $$ |
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Simplify Rational Expressions