Question
Answer
$$\dfrac{6^2-54x+120}{4x^2-20x+16}=\dfrac{-27x+78}{2x^2-10x+8}$$
Explanation
| $$ \begin{aligned}\frac{6^2-54x+120}{4x^2-20x+16}& \xlongequal{ }\frac{36-54x+120}{4x^2-20x+16} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-54x+156}{4x^2-20x+16} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{-27x+78}{2x^2-10x+8}\end{aligned} $$ | |
| ① | Simplify numerator $$ \color{blue}{36} -54x+ \color{blue}{120} = -54x+ \color{blue}{156} $$ |
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