Question
Answer
$$\dfrac{5x^2+x-4}{25x^2-40x+16}=\dfrac{x+1}{5x-4}$$
Explanation
| $$ \begin{aligned}\frac{5x^2+x-4}{25x^2-40x+16}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x+1}{5x-4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{5x^2+x-4}{25x^2-40x+16} $ to $ \dfrac{x+1}{5x-4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5x-4}$. $$ \begin{aligned} \frac{5x^2+x-4}{25x^2-40x+16} & =\frac{ \left( x+1 \right) \cdot \color{blue}{ \left( 5x-4 \right) }}{ \left( 5x-4 \right) \cdot \color{blue}{ \left( 5x-4 \right) }} = \\[1ex] &= \frac{x+1}{5x-4} \end{aligned} $$ |
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