Question
Answer
$$(5n^3+28n^2-53n-35)(n+7)=5n^4+63n^3+143n^2-406n-245$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5n^3+28n^2-53n-35)(n+7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5n^4+63n^3+143n^2-406n-245\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{5n^3+28n^2-53n-35}\right) $ by each term in $ \left( n+7\right) $. $$ \left( \color{blue}{5n^3+28n^2-53n-35}\right) \cdot \left( n+7\right) = 5n^4+35n^3+28n^3+196n^2-53n^2-371n-35n-245 $$ |
| ② | Combine like terms: $$ 5n^4+ \color{blue}{35n^3} + \color{blue}{28n^3} + \color{red}{196n^2} \color{red}{-53n^2} \color{green}{-371n} \color{green}{-35n} -245 = \\ = 5n^4+ \color{blue}{63n^3} + \color{red}{143n^2} \color{green}{-406n} -245 $$ |
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