Question
Answer
$$\dfrac{5h-8}{5h^2-8h}=\dfrac{1}{h}$$
Explanation
| $$ \begin{aligned}\frac{5h-8}{5h^2-8h}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{h}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{5h-8}{5h^2-8h} $ to $ \dfrac{1}{h} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5h-8}$. $$ \begin{aligned} \frac{5h-8}{5h^2-8h} & =\frac{ 1 \cdot \color{blue}{ \left( 5h-8 \right) }}{ h \cdot \color{blue}{ \left( 5h-8 \right) }} = \\[1ex] &= \frac{1}{h} \end{aligned} $$ |
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Simplify Rational Expressions