Question
Answer
$$\dfrac{5b^3}{2}\cdot\dfrac{8}{3}=\dfrac{40b^3}{6}$$
Explanation
| $$ \begin{aligned}\frac{5b^3}{2}\cdot\frac{8}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{40b^3}{6}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{5b^3}{2} $ by $ \dfrac{8}{3} $ to get $ \dfrac{ 40b^3 }{ 6 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{5b^3}{2} \cdot \frac{8}{3} \xlongequal{\text{Step 1}} \frac{ 5b^3 \cdot 8 }{ 2 \cdot 3 } \xlongequal{\text{Step 2}} \frac{ 40b^3 }{ 6 } \end{aligned} $$ |
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Simplify Rational Expressions