| $$ \begin{aligned}\frac{5a-25}{a-5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5\end{aligned} $$ | |
| ① | Simplify $ \dfrac{5a-25}{a-5} $ to $ 5$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a-5}$. $$ \begin{aligned} \frac{5a-25}{a-5} & =\frac{ 5 \cdot \color{blue}{ \left( a-5 \right) }}{ 1 \cdot \color{blue}{ \left( a-5 \right) }} = \\[1ex] &= \frac{5}{1} =5 \end{aligned} $$ |