Question
Answer
$$(4x-7)(6x^2+x-2)=24x^3-38x^2-15x+14$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x-7)(6x^2+x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}24x^3+4x^2-8x-42x^2-7x+14 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}24x^3-38x^2-15x+14\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x-7}\right) $ by each term in $ \left( 6x^2+x-2\right) $. $$ \left( \color{blue}{4x-7}\right) \cdot \left( 6x^2+x-2\right) = 24x^3+4x^2-8x-42x^2-7x+14 $$ |
| ② | Combine like terms: $$ 24x^3+ \color{blue}{4x^2} \color{red}{-8x} \color{blue}{-42x^2} \color{red}{-7x} +14 = 24x^3 \color{blue}{-38x^2} \color{red}{-15x} +14 $$ |
This page was created using
Simplify Rational Expressions