Question
Answer
$$(4x-4)(6x-20)=24x^2-104x+80$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x-4)(6x-20)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}24x^2-80x-24x+80 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}24x^2-104x+80\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x-4}\right) $ by each term in $ \left( 6x-20\right) $. $$ \left( \color{blue}{4x-4}\right) \cdot \left( 6x-20\right) = 24x^2-80x-24x+80 $$ |
| ② | Combine like terms: $$ 24x^2 \color{blue}{-80x} \color{blue}{-24x} +80 = 24x^2 \color{blue}{-104x} +80 $$ |
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