Question
Answer
$$\dfrac{4x^2-24x}{3x-18}=\dfrac{4x}{3}$$
Explanation
| $$ \begin{aligned}\frac{4x^2-24x}{3x-18}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4x}{3}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4x^2-24x}{3x-18} $ to $ \dfrac{4x}{3} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x-6}$. $$ \begin{aligned} \frac{4x^2-24x}{3x-18} & =\frac{ 4x \cdot \color{blue}{ \left( x-6 \right) }}{ 3 \cdot \color{blue}{ \left( x-6 \right) }} = \\[1ex] &= \frac{4x}{3} \end{aligned} $$ |
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Simplify Rational Expressions