Question
Answer
$$\dfrac{4s^4-6s^3}{2s^3-3s^2}=2s$$
Explanation
| $$ \begin{aligned}\frac{4s^4-6s^3}{2s^3-3s^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2s\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4s^4-6s^3}{2s^3-3s^2} $ to $ 2s$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2s^3-3s^2}$. $$ \begin{aligned} \frac{4s^4-6s^3}{2s^3-3s^2} & =\frac{ 2s \cdot \color{blue}{ \left( 2s^3-3s^2 \right) }}{ 1 \cdot \color{blue}{ \left( 2s^3-3s^2 \right) }} = \\[1ex] &= \frac{2s}{1} =2s \end{aligned} $$ |
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Simplify Rational Expressions