Question
Answer
$$\dfrac{4n^2+24n}{n+6}=4n$$
Explanation
| $$ \begin{aligned}\frac{4n^2+24n}{n+6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4n\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4n^2+24n}{n+6} $ to $ 4n$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{n+6}$. $$ \begin{aligned} \frac{4n^2+24n}{n+6} & =\frac{ 4n \cdot \color{blue}{ \left( n+6 \right) }}{ 1 \cdot \color{blue}{ \left( n+6 \right) }} = \\[1ex] &= \frac{4n}{1} =4n \end{aligned} $$ |
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Simplify Rational Expressions