Question
Answer
$$\dfrac{4m^2-m^2}{m+5}\cdot5=\dfrac{15m^2}{m+5}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{4m^2-m^2}{m+5}\cdot5& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3m^2}{m+5}\cdot5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{15m^2}{m+5}\end{aligned} $$ | |
| ① | Simplify numerator $$ \color{blue}{4m^2} \color{blue}{-m^2} = \color{blue}{3m^2} $$ |
| ② | Multiply $ \dfrac{3m^2}{m+5} $ by $ 5 $ to get $ \dfrac{ 15m^2 }{ m+5 } $. Step 1: Write $ 5 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{3m^2}{m+5} \cdot 5 & \xlongequal{\text{Step 1}} \frac{3m^2}{m+5} \cdot \frac{5}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 3m^2 \cdot 5 }{ \left( m+5 \right) \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 15m^2 }{ m+5 } \end{aligned} $$ |
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