Question
Answer
$$\dfrac{4m^2-8mn}{4}mn=\dfrac{4m^3n-8m^2n^2}{4}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{4m^2-8mn}{4}mn& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4m^3-8m^2n}{4}n \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{4m^3n-8m^2n^2}{4}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{4m^2-8mn}{4} $ by $ m $ to get $ \dfrac{ 4m^3-8m^2n }{ 4 } $. Step 1: Write $ m $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{4m^2-8mn}{4} \cdot m & \xlongequal{\text{Step 1}} \frac{4m^2-8mn}{4} \cdot \frac{m}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 4m^2-8mn \right) \cdot m }{ 4 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 4m^3-8m^2n }{ 4 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{4m^3-8m^2n}{4} $ by $ n $ to get $ \dfrac{ 4m^3n-8m^2n^2 }{ 4 } $. Step 1: Write $ n $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{4m^3-8m^2n}{4} \cdot n & \xlongequal{\text{Step 1}} \frac{4m^3-8m^2n}{4} \cdot \frac{n}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 4m^3-8m^2n \right) \cdot n }{ 4 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 4m^3n-8m^2n^2 }{ 4 } \end{aligned} $$ |
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