Question
Answer
$$\dfrac{4d^3-7d^2-11d}{13d+13}=\dfrac{4d^2-11d}{13}$$
Explanation
| $$ \begin{aligned}\frac{4d^3-7d^2-11d}{13d+13}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4d^2-11d}{13}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4d^3-7d^2-11d}{13d+13} $ to $ \dfrac{4d^2-11d}{13} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{d+1}$. $$ \begin{aligned} \frac{4d^3-7d^2-11d}{13d+13} & =\frac{ \left( 4d^2-11d \right) \cdot \color{blue}{ \left( d+1 \right) }}{ 13 \cdot \color{blue}{ \left( d+1 \right) }} = \\[1ex] &= \frac{4d^2-11d}{13} \end{aligned} $$ |
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Simplify Rational Expressions