Question
Answer
$$\dfrac{4a^2-36a}{2a^4-24a^3+54a^2}=\dfrac{2}{a^2-3a}$$
Explanation
| $$ \begin{aligned}\frac{4a^2-36a}{2a^4-24a^3+54a^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2}{a^2-3a}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4a^2-36a}{2a^4-24a^3+54a^2} $ to $ \dfrac{2}{a^2-3a} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2a^2-18a}$. $$ \begin{aligned} \frac{4a^2-36a}{2a^4-24a^3+54a^2} & =\frac{ 2 \cdot \color{blue}{ \left( 2a^2-18a \right) }}{ \left( a^2-3a \right) \cdot \color{blue}{ \left( 2a^2-18a \right) }} = \\[1ex] &= \frac{2}{a^2-3a} \end{aligned} $$ |
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Simplify Rational Expressions